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The external fencing of a circular path around a circular plot of land is 33 m more than its interior fencing. The width of the path around the plot is
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- 5.52 m
- 5.25 m
- 2.55 m
- 2.25 m
- 5.52 m
Correct Option: B
In-radius of circular plot = r metre (let)
Width of path = x metre
∴ Ex radius = (r + x) metre
According to the question 2π (r + x) – 2πr = 33
⇒ 2πr + 2πx – 2πr = 33
⇒ 2πx = 33
| = 2 × | × x = 33 | |
| 7 |
| ⇒ x = | = | metre | ||
| 2 × 22 | 4 |
= 5.25 metre
