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A string of length 24 cm is bent first into a square and then into a right–angled triangle by keeping one side of the square fixed as its base. Then the area of triangle equals to :
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- 24 cm²
- 60 cm²
- 40 cm²
- 28 cm²
- 24 cm²
Correct Option: A
| Side of square = | cm. = 6 cm. | |
| 4 |
Base of triangle = 6 cm.
∵ 6² + 8² = 10² and 6 + 8 + 10 = 24
∴ Height of triangle = 8 cm.
| ∴ Area of triangle = | × 6 × 8 = 24 sq. cm. | |
| 2 |
