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ABCD is a square. Draw an equilateral triangle PBC on side BC considering BC is a base and an equilateral triangle QAC on diagonal AC considering AC is a base. Find the value of
Area of ∆PBC Area ∆QAC
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- 1/2
- 1
- 1/3
- 1/4
- 1/2
Correct Option: A
Side of square = x units
Diagonal of square = √2x units
∴ | = | x² | ||||||
Area of ∆QAC | ||||||||
(√2x)² | ||||||||
4 |
= 1/2