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The length of a side of an equilateral triangle is 8 cm. The area of the region lying between the circum circle and the incircle of the triangle is (Use : π = 22/7)
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50 1 cm² 7 -
50 2 cm² 7 -
75 1 cm² 7 -
75 2 cm² 7
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Correct Option: B
| Radius of in circle = | cm. | |
| 2√3 |
| Radius of circum-circle = | cm. | |
| √3 |
Where a = side of triangle
∴ Required area = Area of circum-circle – area of in–circle
| = π |  | |  | ² | - | | | ² | | ||
| √3 | 2√3 |
| = π | | - | | ||
| 3 | 12 |
| = π | | | |
| 12 |
| = | = | ||
| 12 | 4 |
| = | × | ||
| 7 | 4 |
| = | = 50 | sq. cm. | ||
| 7 | 7 |
