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Two equal circles intersect so that their centres, and the points at which they intersect form a square of side 1 cm. The area (in sq.cm) of the portion that is common to the circles is
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- π/4
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π - 1 2
- π/5
- (√2 – 1)
- π/4
Correct Option: B
Distance between centres = diagonal of square = √2cm.
| ∴ Ex radii = | cm. | |
| √2 |
Required area = Area of ex-circle – area of square
| = | - 1 | |
| 2 |
