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The perimeter of two squares are 40 cm and 24 cm. The perimeter of a third square , whose area is equal to the difference of the area of these squares, is
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- 34 cm
- 32 cm
- 38 cm
- 30 cm
- 34 cm
Correct Option: B
| Side of the first square = | = 10 cm | |
| 4 |
| Side of the second square = | = 6 cm | |
| 4 |
Difference of the area of these squares = (10 × 10 – 6 × 6) cm²
= (100 – 36) cm² = 64 cm²
∴ Area of the third square = 64 cm²
⇒ Side of third square = √64 = 8 cm
∴ Perimeter of this square = (4 × 8) cm = 32 cm
