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If the height of a given cone be doubled and radius of the base remains the same, the ratio of the volume of the given cone to that of the second cone will be
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- 2 : 1
- 1 : 8
- 1 : 2
- 8 : 1
- 2 : 1
Correct Option: C
Case I : When height = h1, radius = r1,
Volume of the cone V1 = | πr1²h1 | |
3 |
Case II,
When height h2 = 2h1,
radius r² = r1 [radius is same] Volume of the cone
V2 = | πr2²h2 | |
3 |
∴ The required ratio = 1 : 2