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If the radius of the base of a cone be doubled and height is left unchanged, then ratio of the volume of new cone to that of the original cone will be :
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- 1 : 4
- 2 : 1
- 1 : 2
- 4 : 1
- 1 : 4
Correct Option: D
| Volume of original cone, Vl = | πr²h | |
| 3 |
Now, radius of new cone, r1= 2r
height, h1 = h
| ∴ Volume V2 = | πr1²h1 | |
| 3 |
| = | π(2r)² × h = | πr²h | ||
| 3 | 3 |
| ∴ | = | πr²h | ||
| V2 | ||||
| V1 | πr²h | |||
| 3 | ||||
= 4 : 1
