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A semicircular sheet of metal of diameter 28 cm is bent into an open conical cup. The capacity of the cup (taking π = 22/7) is
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- 624.26 cm³
- 622.38 cm³
- 622.56 cm³
- 623.20 cm³
- 624.26 cm³
Correct Option: B
Let the radius of the base of cup be r cm, 2πr = π × 14
π r = 7 cm
Slant height = 14 cm;
Height = √14² - 7⊃ = √21 × 7
= 7√3 cm
∴ Capacity of cup = | πr²h | |
3 |
= | × | × 7 × 7 × 7√3 cm | ||
3 | 7 |
= 622.36 cubic cm.