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A cylinder with base radius 8 cm and height 2 cm is melted to form a cone of height 6 cm. The radius of the cone will be
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- 6 cm
- 8 cm
- 4 cm
- 5 cm
- 6 cm
Correct Option: B
Volume of cylinder = πr²h
= (π × 8 × 8 × 2) cu. cm.
= 128 p cu. cm.
If the radius of the base of cone be R cm. then
| πR²H = 128π | ||
| 3 |
→ R² × 6 = 128 × 3
| ⇒ R² = | = 64 | |
| 6 |
⇒ R = √64 = 8 cm.
