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From a point within an equilateral triangle, perpendiculars drawn to the three sides, are 6 cm, 7 cm and 8 cm respectively. the length of the side of the triangle is :
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- 7 cm
- 10.5 cm
- 14√3 cm
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14√3 cm 3
- 7 cm
Correct Option: C
Let ABC be equilateral triangle of side a cm and P be a point inside it.
From the figure, Area of ∆APB + Area of ∆PBC + Area of ∆APC = Area of ∆ABC
| ⇒ | × a × 6 + | × a × 7 + | × a × 8 = | a² | ||||
| 2 | 2 | 2 | 4 |
| ⇒ | a (6 + 7 + 8) = | a² | ||
| 2 | 4 |
| ⇒ | = | a² | ||
| 2 | 4 |
| ⇒ a = | × | = 14√3 cm. | ||
| 2 | √3 |