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In a fixed time, a boy swims double the distance along the current that he swims against the current. If the speed of the current is 3 km/hr, the speed of the boy in still water is
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- 6 km/hr
- 9 km/hr
- 10 km/hr
- 12 km/hr
- 6 km/hr
Correct Option: B
Let the rate of swimming in still water be p kmph
∴ Rate down-stream = (p + 3) kmph
∴ Rate up-stream = (p – 3) kmph
According to the question,
(p + 3) t = 2 (p – 3) × t
⇒ p + 3 = 2p – 6
⇒ p = 9 kmph
Using the given formula :
Here, t1 = 2k , t2 = k
Speed of Stream = 3 km/hr
∴ | = | ||
Speed of Stream | t1 - t2 |
= | |||
3 | 2k - k |
Speed of Boy = 9 km/hr