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  1. A man goes downstream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the stream are 10 km/hr and 4 km/ hr respectively, the distance of the destination from the starting place is
    1. 16 km
    2. 18 km
    3. 21 km
    4. 25 km
Correct Option: C

Let the distance of the destination from the starting point be d km.
Rate downstream = (10 + 4) kmph = 14 kmph
Rate upstream = (10 – 4) kmph = 6 kmph
According to the question,

d
+
d
= 5
146

3d + 7d
= 5
42

⇒ 10d = 42 × 5
⇒ d =
42 × 5
= 21 km
10

We can find the required answer with the help of given formula :
Here, p = 10, q = 4, t = 5
d =
t(p² - q²)
2p

d =
5(10² - 4²)
2 × 10

d =
5(100 - 16)
2 × 10

d =
84
= 21
4



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