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A man goes downstream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the stream are 10 km/hr and 4 km/ hr respectively, the distance of the destination from the starting place is
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- 16 km
- 18 km
- 21 km
- 25 km
- 16 km
Correct Option: C
Let the distance of the destination from the starting point be d km.
Rate downstream = (10 + 4) kmph = 14 kmph
Rate upstream = (10 – 4) kmph = 6 kmph
According to the question,
+ | = 5 | ||
14 | 6 |
⇒ | = 5 | |
42 |
⇒ 10d = 42 × 5
⇒ d = | = 21 km | |
10 |
We can find the required answer with the help of given formula :
Here, p = 10, q = 4, t = 5
d = | |
2p |
d = | |
2 × 10 |
d = | |
2 × 10 |
d = | = 21 | |
4 |