If log (0.57) = 1.756 then the value of log 57 + log (0.57)³

Given in question , log 57 + log (0.57)³ + log √0.57
{ ∴ log ( ab ) = log a + log b and log ( a )ⁿ = nloga }

log 57 + log (0.57)³ + log ( 0.57 )^{1 /2} = log [(0.57) × 100]+ 3 log 0.57 +	1	log 0.57
	2

= log 100 + log (0.57) + 3 log (0.57) +	1	log (0.57)
	2

= 2 +	9	log(0.57) [∵ log 100 = log 10² = 2log 10 = 2]
	2

= 2 +	9	× (1.756)
	2

= 2 +	9	× 0.756 -	9
	2		2

= 2 + 3.402 - 4.5 = 0.902