Aptitude miscellaneous Easy Questions and Answers | Page - 1

Aptitude miscellaneous

If log 2 = 0.3010, then log 5 equals :

1. 0.3010
1. 0.6990
1. 0.7525
1. Given log 2, it is not possible to calculate log 5

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We can write as ,
Log 5 = log 10
2

Using given formula , log a = log a - log b
b

Correct Option: B

We can write as ,
Log 5 = log 10
2

Using given formula , log a = log a - log b
b

Log 5 = log 10 – log 2
Log 5 = 1 – 0.3010 = 0.6990

The simplified form of log 75 - 2log 5 + log 32 is :
16 9 243

1. log 2
1. 2log 2
1. log 3
1. log 5

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Given that , Log 75 - 2 Log 5 + Log 32
16 9 243

= Log 5² × 3 - 2 Log 5 + Log 2⁵
2⁴ ^3² 3⁵

Correct Option: A

Given that , Log 75 - 2 Log 5 + Log 32
16 9 243

= Log 5² × 3 - 2 Log 5 + Log 2⁵
2⁴ ^3² 3⁵

Using given formula , log a = log a - log b and log ( ab ) = log a + log b
b

Required answer = 2Log 5 + Log 3 – 4Log 2 – 2Log 5 + 4Log 3 + 5Log 2 – 5Log 3 = Log 2