If the number of items of a set A be n(A) = 40, n(B) = 26

If the number of items of a set A be n(A) = 40, n(B) = 26 and n(A⋂B) = 16, then n (A⋃B) is equal to

Given , n(A) = 40, n(B) = 26 and n(A⋂B) = 16,
As we know that ,
n(A∪B) = n(A) + n(B) - n(A ∩ B)
n(A∪B) = 40 + 26 -16 = 50
Therefore , n(A∪B) = 50