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A die with faces numbered from 1 to 6 is thrown twice. The probability, that the numbers shown up differ by 2, is
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1 9 -
2 9 -
3 9 -
4 9
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Correct Option: B
As per the given in question ,
Total possible outcomes n( S ) = 6 × 6 = 36
Favourable number of cases n( E ) = (1, 3), (3, 1), (2, 4), (4,2), (3,5), (5,3), (4,6), (6,4) = 8
| ∴ Required probability = | ||
| n( S ) |
| Required probability = | = | ||
| 36 | 9 |
