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The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is ?
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- 74
- 94
- 184
- 364
Correct Option: D
Let the least multiple of 7 be x, which when divided by 90 leaves the remainder 4. Then, x is of the form 90k + 4
Now, the minimum value of k for which 90k + 4 divisible by 7 is 4
∴ x = 90 x 4 + 4
= 364
