Dinesh bought two radios for $ 1,920. He sold one at a profit

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Dinesh bought two radios for $ 1,920. He sold one at a profit of 20% and the other at a loss of (50 / 3)% . If the selling price of both radios are same, the cost prices of the two radios are

1. $ 800 and $ 1,120
2. $ 840 and $ 1,080
3. $ 860 and $ 1,060
4. $ 900 and $ 1,020

Let C.P. of radio sold on gain = x
C.P. of radio sold on loss = $ (1920 – x)
According to question ,

∴ x ×	120
	100

⇒ x × 120 = (1920 - x) ×	280
	3

⇒ 3x = (1920 - x) ×	7
	3

⇒ 9x + 7x = 1920 × 7
⇒ 16x = 1920 × 7
⇒ x = $840
∴ C.P. of second radio = $ 1080