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In a school 40% of the students play football and 50% play cricket. If 18% of the students neither play football nor cricket, the percentage of the students playing both is :
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- 40%
- 32%
- 22%
- 8%
Correct Option: D
As per the given details in question ,
Since 18% of the students neither play football nor cricket. It means 82% of the students either play football or cricket or both.
Using set theory
∴ n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
⇒ 82 = 40 + 50 – n(A ∩ B)
⇒ n(A ∩ B) = 90 – 82 = 8
∴ 8% students play both games.
