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An ore contains 25% of an alloy that has 90% iron. Other than this, in the remaining 75% of the ore, there is no iron. To obtain 60 kg of pure iron, the quantity of the ore needed (in kgs) is approximately :
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- 250.57
- 266.67
- 275.23
- 300
Correct Option: B
In 4 kg of ore iron = 0.9 kg.
∴ Quantity of ore for 60 kg of iron = | = 266.67 kg | 0.9 |