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20 litres of a mixture contains 20% alcohol and the rest water. If 4 litres of water be mixed in it, the percentage of alcohol in the new mixture will be
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33 1 % 3 -
16 2 % 3 - 25%
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12 1 % 2
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Correct Option: B
In 20 litres of mixture,
| Alcohol ⇒ | = 4 litres | 100 |
Water ⇒ 20 - 4 = 16 litres
On adding 4 litres of water,
Quantity of water ⇒ 16 + 4 = 20 litres
Quantity of mixture = 24 litres
| ∴ Required percent = | × 100 | 24 |
| Required percent = | = 16 | % | ||
| 3 | 3 |
