The HCF and product of two numbers are 15 and 6300 respectively.

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The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the numbers is

1. 4
2. 3
3. 2
4. 1

Correct Option: C

Here , HCF = 15
Let the number be 15p and 15q, where p and q are co – prime.
With the help of the given formula ,
HCF × LCM = Product of two numbers
∴ 15p × 15q = 6300

⇒ pq =	6300	= 28
	15 × 15

So, two pairs are ( 7 , 4 ) and ( 14 , 2 ) .
Hence , required answer is 2.