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The product of two numbers is 2028 and their HCF is 13. The number of such pairs is
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- 1
- 2
- 3
- 4
Correct Option: B
Here, HCF = 13
Let the numbers be 13p and 13q ,where p and q are Prime to each other.
Now, 13p × 13q = 2028
| ⇒ pq = | = 12 | 13 × 13 |
The possible pairs are :- ( 1 , 12 ) , ( 3 , 4 ) , ( 2 , 6 )
But the 2 and 6 are not co-prime.
∴ The required no. of pairs = 2
