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The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is :
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- 46
- 48
- 50
- 56
Correct Option: C
Here , Remainder ( r ) = 2
As we know that When a number is divided by a, b , c or d leaving same remainder ‘r’ in each case then that number must be k + r where k is LCM of a, b , c and d.
So , L.C.M. of 4, 6, 8, 12 and 16 = k = 48
∴ Required number = k + r = 48 + 2 = 50
