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The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is:
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- 2520
- 842
- 2522
- 840
Correct Option: C
According to question ,
LCM of 4, 5, 6, 7 and 8
LCM of 4, 5, 6, 7 and 8 = 2 × 2 × 2 × 3 × 5 × 7 = 840.
Let required number be 840K + 2 which is multiple of 13.
Least value of K for which ( 840K + 2 ) is divisible by 13 is K = 3
∴ Required number = 840 × 3 + 2
Required number = 2520 + 2 = 2522