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Find the largest number of four digits such that on dividing by 15, 18, 21 and 24 the remainders are 11, 14, 17 and 20 respectively.
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- 6557
- 7556
- 5675
- 7664
Correct Option: B
As per the given details in question , we have
15 = 3 × 5
18 = 32 × 2
21 = 3 × 7
24 = 23 × 3
LCM of 15 , 18 , 21 and 24 = 8 × 9 × 5 × 7 = 2520
The largest number of four digits = 9999
Required number = 9999 – 2439 – 4 = 7556
(Because 15 – 11 = 4
18 – 14 = 4
21 – 17 = 4
24 – 20 = 4)