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The least multiple of 7, which leaves the remainder 4, when divided by any of 6, 9, 15 and 18, is
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- 76
- 94
- 184
- 364
Correct Option: D
LCM of 6, 9, 15 and 18
∴ LCM = 2 × 3 × 3 × 5 = 90
∴ Required number = 90k + 4, which must be a multiple of 7 for some value of k.
For k = 4,
Required Number = 90 × 4 + 4 = 364, which is exactly divisible by 7.
