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The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder is
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- 1677
- 1683
- 2523
- 3363
Correct Option: B
The LCM of 5, 6, 7 and 8 = 840
∴ Required number = 840k + 3 , which is exactly divisible by 9 for some value of k.
Now, 840k + 3 = 93 × 9k + (3k + 3)
When k = 2 , 3k + 3 = 9, which is divisible by 9.
∴ Required number = 840k + 3 = 840 × 2 + 3 = 1683
