Home » Aptitude » LCM and HCF » Question
  1. The smallest number, which, when divided by 12 or 10 or 8, leaves remainder 6 in each case, is
    1. 246
    2. 186
    3. 126
    4. 66
Correct Option: C

As we know that when a number is divided by a, b or c leaving remainders p, q and r respectively such that the difference between divisor and remainder in each case is same i.e., (a – p) = (b – q) = (c – r) = t (say) then that (least) number must be in the form of (k – t), where k is LCM of a , b and c .
The smallest number divisible by 12 or 10 or 8
= LCM of 12, 10 and 8 = 120
remainder = 6
∴ Required number = 120 + 6 = 126



Your comments will be displayed only after manual approval.