Correct Option: C

As we know that when a number is divided by a, b or c leaving remainders p, q and r respectively such that the difference between divisor and remainder in each case is same i.e., (a – p) = (b – q) = (c – r) = t (say) then that (least) number must be in the form of (k – t), where k is LCM of a , b and c .
The smallest number divisible by 12 or 10 or 8
= LCM of 12, 10 and 8 = 120
remainder = 6
∴ Required number = 120 + 6 = 126