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The largest 4-digit number exactly divisible by each of 12, 15, 18 and 27 is
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- 9690
- 9720
- 9930
- 9960
Correct Option: B
As we know that Greatest n digit number which when divided by three numbers p,q,r leaves no remainder will be Required Number = (n – digit greatest number) – R , R is the remainder obtained on dividing greatest n digit number by L.C.M of p.q,r.
The largest number of 4-digits is 9999. L.C.M. of divisors
LCM = 2 × 2 × 3 × 3 × 3 × 5 = 540
Divide 9999 by 540, now we get 279 as remainder.
9999 – 279 = 9720
Hence, 9720 is the largest 4-digit number exactly divisible by each of 12, 15, 18 and 27.