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  1. The smallest number, which when increased by 5 is divisible by each of 24,32, 36 and 564, is
    1. 869
    2. 859
    3. 4320
    4. 427
Correct Option: B

Required number = (LCM of 24, 32, 36 and 54) – 5
Now,LCM of 24, 32, 36 and 54

LCM = 2 × 2 × 2 × 3 × 3 × 3 × 4 = 864
∴ Required number = 864 – 5 = 859



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