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The greatest number, by which 1657 and 2037 are divided to give remainders 6 and 5 respectively, is
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- 127
- 133
- 235
- 305
Correct Option: A
As we know that the largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r).
We have to find HCF of (1657 – 6 = 1651) and
(2037 – 5 = 2032)
1651 = 13 × 127
2032 = 16 × 127
∴ HCF = 127
So, required number will be 127.
