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Two numbers, both greater than 29, have HCF 29 and LCM 4147. The sum of the numbers is :
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- 966
- 696
- 669
- 666
Correct Option: B
Let the number be 29p and 29q respectively , where p and q are prime to each other.
∴ LCM of 29p and 29q = 29pq
Now, 29pq = 4147
| ∴ pq = | = 143 | 29 |
Thus pq = 11 × 13
Here , p = 11 , q = 13
∴ Numbers are 29 × 11 = 319 and 29 × 13 = 377
∴ Required sum = 377 + 319 = 696
