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The sum of two numbers is 84 and their HCF is 12. Total number of such pairs of number is
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- 2
- 3
- 4
- 5
Correct Option: B
Given , HCF = 12
∴ Numbers = 12p and 12q , where p and q are prime to each other.
∴ 12p + 12q = 84
⇒ 12 (p + q) = 84
⇒ p + q = | = 7 | 12 |
∴ Possible pairs of numbers satisfying this condition = (1 , 6), (2 , 5) and (3 , 4).
Hence three pairs are of required numbers.