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The sum of two numbers is 36 and their H.C.F. is 4. How many pairs of such numbers are possible ?
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- 1
- 2
- 3
- 4
Correct Option: C
Given Here , HCF of two numbers = 4.
Hence, the numbers can be given by 4p and 4q , where p and q are co-prime. Then,
4p + 4q = 36 ⇒ 4 (p + q) = 36
⇒ p + q = 9
Possible pairs satisfying this condition are : (1 , 8), (4 , 5), (2 , 7)
Hence , number of possible pairs is 3.
