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The greatest number, that divides 122 and 243 leaving respectively 2 and 3 as remainders, is
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- 12
- 24
- 30
- 120
Correct Option: D
As we know that the largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r).
Clearly, 122 – 2 = 120 and 243 – 3 = 240 are exactly divisible by the required number.
∴ Required number = HCF of 120 and 240 = 120