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Three plots having an area of 132, 204 and 228 square metres respectively are to be subdivided into equal vegetable beds. If the breadth of a bed is 3 metres, find the maximum length that a bed can have.
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- 14 metres
- 4 metres
- 24 metres
- 6 metres
Correct Option: B
The maximum area a bed can have will be the greatest divisor of three plots.
we find the HCF of 132, 204 and 228
Now, HCF of 132 and 204
The HCF of 132 and 204 = 12
The required HCF = HCF of 12 and 228.
Hence, the greatest area of the equalised bed = 12 sq.metres
| ∴ Maximum length of the bed = | = | = 4 metres | Breadth | 3 |
