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Find the greatest number which will divide 42, 49 and 56 and leave remainders 6, 7 and 8 respectively.
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- 6
- 8
- 12
- 24
Correct Option: A
Take the HCF of (42 – 6) = 36, (49 – 7) = 42 and (56 – 8) = 48
We find the HCF of 36 , 42 and 48
And, HCF of 6 and 48 is also 6.
So, the required greatest number will be 6.
