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  1. The marked price of a watch was ₹ 720. A man bought the same for ₹ 550.80, after getting two successive discounts, the first at 10 %. What was the second discount rate?
    1. 12%
    2. 14%
    3. 15%
    4. 18%
Correct Option: C

Marked price = ₹ 720
Actual price = ₹ 550.80
First discount D1 = 10 %
Let the second discount = D2 %
As we know the formula,

Successive discounts of D1 % and D2 % is overall equals to = 10 + D2
10 × D2
%
100

= 10 + D2
10 × D2
100

= 10 + D2
D2
10

= 10 + D2 - 0.1D2
= 10 + 0.9D2
According to question,
720 x ( 100 - 10 - 0.9D2) % = 550.80
⇒  720 x ( 90 - 0.9D2) = 550.80 x 100
⇒  90 - 0.9D2 =
55080
720

⇒  90 - 0.9D2 =
5508
72

⇒  90 - 0.9D2 =
612
8

⇒  0.9D2 = 90 -
612
8

⇒  0.9D2 =
720 - 612
8

⇒  0.9D2 =
108
8

⇒  0.9D2 =
27
2

⇒  D2 =
27
× 0.9
2

⇒  D2 = 27 ×
10
× 9
2

⇒  D2 = 3 ×
10
=
30
22

∴  Second discount = 15%

2nd Method to solve this question.
Here, Marked price = ₹ 720
Selling price = ₹ 550.80
First discount D1 = 10 %
Let assume the second discount = D2 %
As we know the formula,
Selling Price = Market Price
100 − D1
100 − D2
100100

550.80 = 720
100 − 10
100 − D2
100100

⇒  550.80 = 720 ×
90
×
100 - D2
100100

⇒  550.80 = 72 ×
9
×
100 - D2
1100

⇒  550.80 = 72 × 9 x
(100 - D2)
100

⇒  550.80 x 100 = 72 × 9 x ( 100 - D2 )
⇒  55080 = 648 x ( 100 - D2 )
⇒  55080 = 648 x 100 - 648 x D2
⇒  55080 = 64800 - 648 x D2
⇒  648 x D2 = 64800 - 55080
⇒  648 x D2 = 9720
⇒  D2 =
9720
648

⇒  D2 = 15 %



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