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The marked price of a watch is 800. A shopkeeper gives two successive discounts and sells the watch at 612. If the first discount is 10%, the second discount is :
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- 10%
- 12%
- 15%
- 20%
Correct Option: C
Let the second discount be D2 %.
Then, 90 % of (100 – D2) % of 800 = 612
⇒ | × | × 800 = 612 | ||
100 | 100 |
⇒ 100 − D2 = | = 85 | |
90 × 8 |
⇒ D2 = 100 – 85 = 15%
Another method to solve :
Here, M.P. = Rs. 800, S.P. = Rs. 612, D1 = 10%, D2 = ?
S.P. = M.P. | ![]() | ![]() | ![]() | ![]() | ||
100 | 100 |
612 = 800 × | ![]() | ![]() | ![]() | ![]() | ||
100 | 100 |
612 = 800 × | × | ||
100 | 100 |
= 100 × D2 | |
72 |
D2 = | |
72 |
D2 = | = 15% | |
72 |