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From 4 children, 2 women and 4 men, 4 person are selected. The probability that there are exactly 2 children among the selected persons, is
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- 11/21
- 9/21
- 10/21
- 5/21
- None of the above
Correct Option: B
Total number of cases = 10c4
Favorable number of cases = 4c2. 6c2
{Since, we are to select 2 children out of 4 and remaining 2 persons are to be selected from remaining 6 persons ( 2W + 4M)}
∴ required Probability = 4c2 . 6c2 / 10c4
= [{(4 x 3) / (2 x 1)} x {(6 x 5) / (2 x 1)}] / [ (10 x 9 x 8 x 7) / (4 x 3 x 2 x 1)]
= [(12/2) x (30/2)] / 210
= 90 / 210
= 9 /12
