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Discussion

  1. Calculate the amount of water which should be added to 80% solution of Sulphuric acid to make it a 50% solution?
    1. 60cc
    2. 80cc
    3. 75cc
    4. 70cc
  1. Correct Option: A

    Concentration of Sulphuric acid = 80%
    So in a 100cc, Sulphuric acid = 80cc and water = 20cc
    Let x be the amount of water added to make concentration of 50%
    ⇒80/(100+x) = 50/100
    ⇒ 80/(100+x) = 1/2
    ∴ x = 60cc


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