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In how many different ways, 5 boys and 5 girls can sit on a circular table, so that the boys and girls are alternate ?
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- 2880
- 2800
- 2680
- 2280
- None of the above
Correct Option: A
After fixing up one boy on the table, the remaining can be arranged in 4 ! ways, but boys and girls have to be alternate. There will be 5 places, one place each between two boys. These 5 place can be filled by 5 girls in 5 ! ways .
Hence, by the principle of multiplication, the required number of ways = 4 ! x 5 ! = 2880
