In how many ways, the letters of the word 'ARMOUR' can be arranged ?
720
300
640
350
None of the above
Correct Option: E
Number of arrangements n ! /( p ! q ! r ! ) Total letters = 6, but R has come twice. So, required number of arrangements = 6 ! / 2 ! = (6 x 5 x 4 x 3 x 2 !) / 2 ! = 360