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  1. What was the day of the week on 5th June, 2002 ?
    1. Wednesday
    2. Saturday
    3. Friday
    4. Monday
    5. None of the above
Correct Option: A

Period upto 5th June, 2002 = (2001 yr + Period from 1.1.2002 to 5.6.2002)
∴ Odd days in 1600 yr = 0
Odd days in 400 yr = 0
Odd days in 1 ordinary year = 1
Odd days in 2001 year = (0 + 0 + 1) = 1

Number of days from 1.1.2002 to 5.6.2002
January + February + March + April + May + June
= 31 + 28 + 31 + 30 + 31 + 5
= 156 days = 22 weeks + 2 days
= 2 odd days

∴ Total number of odd days = (1 + 2) = 3
∴ The required day is Wednesday.



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