∛x6 ÷ ∛x12 × x- 3 × ∛x9

∛x⁶ ÷ ∛x¹² × x^{- 3} × ∛x⁹

=	(x⁶)^1/3	× x^{- 3} ×(x⁹)^1/3
	(x¹²)^1/6

	6 ×	₁			9 ×	₁
x	6 ×	³	× x^{- 3}×	x	9 ×	³

=	x² × x^{- 3} × x³	× x⁰ = 1
	x²