Ⅰ. 18x2 + 18x + 4 = 0 Ⅱ. 12y2 + 29y + 14 =0

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Direction: In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer
( 1 ) x < y
( 2 ) x > y
( 3 ) x ≤ y
( 4 ) x ≥ y
( 5 ) x = y

Ⅰ. 18x² + 18x + 4 = 0
Ⅱ. 12y² + 29y + 14 =0

1. 1
2. 2
3. 3
4. 4
5. 5

Correct Option: D

From the given above question , we have
From equation Ⅰ. 18x² + 18x + 4 = 0
⇒ 9x² + 9x + 2 = 0
⇒ (3x + 2)(3x + 1) = 0

∴ x = -	2	or, -	1
	3		3

From equation Ⅱ. 12y² + 29y + 14 =0
⇒ (3y + 2)(4y + 7) = 0

∴ y = -	2	or, -	7
	3		4

Hence, x ≥ y is correct answer .