Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
( 1 ) x > y
( 2 ) x ≥ y
( 3 ) x < y
( 4 ) x ≤ y
( 5 ) x = y or the relationship cannot be established.
-
Ⅰ. √500x + √402 = 0
Ⅱ. √360y + ( 200 )1/2 = 0
-
- 1
- 2
- 3
- 4
- 5
Correct Option: C
As per the given above equations , we can say that
Ⅰ.
√500x + √402 = 0
⇒ √500x = - √402
∴ x = - √( 402/500 ) = - √( 400/500 ) = - 0.9
Ⅱ. √360y + ( 200 )1/2 = 0
⇒ √360y = - √200
∴
y = - √( 200 / 360 ) = - 0.74
Clearly, we can see that x < y is required answer .
