Direction: Study the given information carefully and answer the question that follow.
An urn contains 6 red, 4 blue, 2 green and 3 yellow marbles.
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If four marbles are picked at random, what is the probability that one is green, two are blue and one is red ?
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- 24/455
- 13/35
- 11/15
- 7/91
Correct Option: A
Ways of selection of 4 marbles = n(S) = 15C4
Ways of selection of one green marbles = n(E1) = 2C1
Ways of selection of two blue marbles = n(E2)=4C2
Ways of selection of one red marble = n(E3) = 6C1
∴ Required probability = (2C1 x 4C2 x 6C1) / (15C4) = 24/455